Physics behind Dinosaur Weight Argument
The equations for our effective weight on a spinning globe W = GMm/(R*R) - v*vm/R the first term is force due to gravity, the second term is centripetal force. W is the effective weight (downward force felt by the object), G is the gravitational constant, M is the mass of the Earth, R is the radius of the earth, m is the mass of the object on earth, v is the velocity that the earth is spinning which is greatest for an object on the equator and zero for an object at the rotational poles. W = 9.8*m - .034*m The force due to gravity is the familiar 9.8 meters per seconds squared. The second term uses the velocity v = 465 meters/sec and a radiusof the earth as R= 6,356,000 meters. The second term is very small, less that 1% of our effective weight.
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Size Limit The largest land animal today positioned at the equator will feel an effective weight of Wt = (9.8 - .034)Mt where Wt is max weight today and Mt is mass today, of the largest land animal.
where Wd is max weight of the dinosaur, Md is mass of the dinosaur, k is a factor increase in velocity. Think of k as an increase in the rotation speed of the earth in terms of today's rotation. If k=2 the earth would rotate twice as fast. Wt = Wd
Md/Mt = (9.8-.034)/(9.8 - .034*k*k)
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